When u+v Equals u-v - Orthogonality Proof architecture diagram

About This Architecture

Orthogonality proof demonstrating when the sum and difference of two vectors have equal magnitude in abstract vector spaces. The diagram walks through a rigorous algebraic proof starting from the hypothesis ||u+v|| = ||u-v||, squaring both sides, expanding using inner products, and simplifying to derive u·v = 0. This proof establishes the fundamental geometric principle that two vectors are orthogonal if and only if the diagonals of their parallelogram are equal in length. Fork this diagram to customize the proof steps, add geometric visualizations, or adapt it for teaching linear algebra and functional analysis courses.

People also ask

When does u+v equal u-v for vectors in an abstract vector space?

The equation ||u+v|| = ||u-v|| holds if and only if u and v are orthogonal, meaning their inner product u·v = 0. This proof expands both sides using the inner product definition, cancels common terms, and derives that 4(u·v) = 0, establishing orthogonality as the necessary and sufficient condition.

When u+v Equals u-v - Orthogonality Proof

Autointermediatelinear algebraorthogonalityvector spacesinner productmathematical proofabstract algebra
Domain: OtherAudience: mathematics students and linear algebra instructors
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Created by

May 12, 2026

Updated

September 26, 2026 at 1:24 AM

Type

others

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